Edit Validate IsValidInteger Example 3

-

 Hi All,

In this blog we will see example 3



Follow below steps

ID = IsValidInteger


Java Source

try

{

Integer.parseInt(theValue.toString());

}

catch(java.lang.NumberFormatException  ex)

{

theProperty.addMessage("Please enter a valid number, possible cause are");

theProperty.addMessage("1. The length of entered number is not valid. 2. The entered number contains a decimal value ");

}

return true;


Thank you!! Will see you all in next blog post 😊. 


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